为什么在wincc c脚本内定义的变量，不与wincc变量链接，内部变量就不动作？
郑志武
发布于2013-10-21 01:44
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有c脚本按照下面做，脚本变量lss1可以正常动作，如下
#include"apdefap.h"
intgscaction(void)
{
#pragmaoption(mbcs)
#pragmacode()
charfilename[20]="";
doublerow=gettagdouble("行数");//return-type:double
doublelsj=gettagword("ls");
doublelsjj1=gettagword("lsjj");
doubleaa=lsj-lsjj1;
__object*pexcel=null;
row=row+1;
lsjj1=lsj;
pexcel=__object_create("excel.application");
pexcel->workbooks->open("e:\jilu.xlsx");
pexcel->worksheets("sheet1")->cells(row,2)->value=aa;
pexcel->activeworkbook->save;
pexcel->workbooks->close();
pexcel->quit();
__object_delete(pexcel);
settagdouble("行数",row);//return-type:bool
settagdouble("lsjj",lsjj1);
return0;
}
一旦我把doublelsjj1=gettagword("lsjj");不与外部变量lsjj链接，改成doublelsjj1;并且删除settagdouble("lsjj",lsjj1);这一行，内部变量lsjj1在脚本里始终不动作，就是不能执行lsjj1=lsj;，一直都是0.请高手解答，万分感谢！！！
问题补充：
我想执行的脚本是内容是aa=lsj-lsjj1然后使lsjj1=lsj,再把aa写到excel里，lsjj1只是脚本中的中间变量，lsj连接着外部的wincc变量ls,这个变量始终变化，我就想算wincc外部变量ls在我规定的触发器时间内有了多少变化
